파이썬사용했는데 안되는 이유

문의 시, 사용하시는 개발환경과 디벨로퍼스 앱ID를 알려주세요.


안녕하세요 파이썬으로 엑셀에 연결하고 그후 좌표를찾아 길찾기 환경을 만들려고 합니다 그런데 안되는 곳이 있네요 안되는 이유가 뭔가요
import pandas as pd

import requests

api_key = “````”

df = pd.read_excel(“C:\Users\user\Desktop\새 폴더\123.xlsx”)

addresses = df[“주소”].tolist()[:500]

url = “https://dapi.kakao.com/v2/local/geo/coord2address.json

headers = {“Authorization”: f"KakaoAK (```````)"}

def get_address_by_coords(coords):

params = {"x": coords[0], "y": coords[1]}      

response = requests.get(url, headers=headers, params=params)        

result_json = response.json()      

address = result_json["documents"][0]["address"]["address_name"]        

return address      

path = []

for address in addresses:

params = {"query": address}    

response = requests.get(url, headers=headers, params=params)        

result_json = response.json()      

coords = result_json["documents"][0]["y"], result_json["documents"][0]["x"]    

path.append(",".join(map(str, coords)))    

def calculate_distance(coords1, coords2):

url = (    

    f"https://dapi.kakao.com/v2/local/geo/transcoord.json?"    

    f"y1={coords1[1]}&x1={coords1[0]}&y2={coords2[1]}&x2={coords2[0]}&input_coord=WGS84&output_coord=WGS84"    

)      

response = requests.get(url, headers=headers)      

result_json = response.json()      

distance = result_json["documents"][0]["distance"]      

return distance    

distances = {}

for i in range(len(path)):

for j in range(i, len(path)):      

    if i == j:      

        distances[(i, j)] = float("inf")        

    else:      

        coords1 = path[i].split(",")        

        coords2 = path[j].split(",")        

        distance = calculate_distance(coords1, coords2)    

        distances[(i, j)] = distance        

        distances[(j, i)] = distance        

sorted_distances = sorted(distances.items(), key=lambda x: x[1])

sorted_distances = [item for item in sorted_distances if item[1] != float(“inf”)]

visited = []

result_path = []

for item in sorted_distances:

if item[0][0] not in visited:      

    visited.append(item[0][0])      

    result_path.append(addresses[item[0][0]])      

if item[0][1] not in visited:      

    visited.append(item[0][1])      

    result_path.append(addresses[item[0][1]])      

if len(result_path) == len(addresses):      

    break      

print(result_path)